Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 4 - Section 4.3 - Right Triangle Trigonometry - Exercise Set - Page 561: 45



Work Step by Step

Solve. $1+\sin^2 40^{\circ}+\sin^2 50^{\circ}$ We have $= 1+\sin^2 (90^{\circ}-50^{\circ})+\sin^2 50^{\circ}$ or, $=1+\cos^2 50^{\circ}+\sin^2 50^{\circ}$ or, $=1+1$ or, $=2$
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