Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 4 - Section 4.3 - Right Triangle Trigonometry - Exercise Set - Page 561: 33


$c \approx 41$ m

Work Step by Step

RECALL: (1) $\sin{\theta} = \dfrac{\text{opposite side}}{\text{hypotenuse}}$ (2) $\cos{\theta} = \dfrac{\text{adjacent side}}{\text{hypotenuse}}$ (3) $\tan{\theta} = \dfrac{\text{opposite side}}{\text{adjacent side}}$ Use (1) above to obtain: $\sin{23^o}=\dfrac{16}{c} \\c(\sin{23^o})=16 \\c = \dfrac{16}{\sin{23^o}}$ Use a calculator in DEG mode to obtain $\\c=40.94887464 \\c \approx 41 \text{ m}$
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