Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 4 - Section 4.3 - Right Triangle Trigonometry - Exercise Set: 30

Answer

$a \approx 18$ cm

Work Step by Step

RECALL: (1) $\sin{\theta} = \dfrac{\text{opposite side}}{\text{hypotenuse}}$ (2) $\cos{\theta} = \dfrac{\text{adjacent side}}{\text{hypotenuse}}$ (3) $\tan{\theta} = \dfrac{\text{opposite side}}{\text{adjacent side}}$ Use (3) above to obtain: $\tan{61^o}=\dfrac{a}{10} \\a=10(\tan{61^o})$ Use a calculator in DEG mode to obtain $\\a=18.04047755 \\a \approx 18$ cm
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