Answer
$0$
Work Step by Step
Solve. $\dfrac{\tan \dfrac{\pi}{3}}{2}-\dfrac{1}{\sec \dfrac{\pi}{6}}$
We have $\dfrac{\tan \dfrac{\pi}{3}}{2}-\dfrac{1}{\sec \dfrac{\pi}{6}}=\dfrac{\sqrt 3}{2}- \dfrac{1}{2/\sqrt 3}$
or, $= \dfrac{\sqrt 3}{2}-\dfrac{\sqrt 3}{2}$
or, $=0$
