Answer
$-1$
Work Step by Step
Since, $\sec^2 \theta =1+\tan^2 \theta $
Here, $\theta = 1.4^{\circ}$
We have: $ \tan^2 1.4^{\circ}-\sec^2 1.4^{\circ} $
or, $= \tan^2 1.4^{\circ}-(1+\tan^2 1.4^{\circ} ) $
or, $=-1$
Precalculus (6th Edition) Blitzer
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13446-914-3
ISBN 13:
978-0-13446-914-0
Chapter 4 - Review Exercises - Page 644: 30
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