Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 4 - Review Exercises - Page 644: 20


$42411.5$ feet per minute

Work Step by Step

Since, $ s= r \theta $ The linear speed for the tip of the propeller is given by: $ 2 \pi r \times 2250$ or, $2 \pi r \times 2250=6\pi \times 2250$ Thus, we have (in feet per minute) $=2250 \times 6 \times 3.142 =42411.5$ feet per minute
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