## Precalculus (6th Edition) Blitzer

$\sin \theta =\dfrac{y}{r}=\dfrac{-15}{17} \\ \cos \theta =\dfrac{x}{r}=\dfrac{8}{17} \\ \tan \theta =\dfrac{y}{x}=\dfrac{-15}{8}$ and $\csc \theta =\dfrac{r}{y}=\dfrac{-17}{15} \\ \sec \theta =\dfrac{r}{x}=\dfrac{17}{8} \\ \cot \theta =\dfrac{x}{y}=\dfrac{-8}{15}$
The trigonometric ratios are as follows: $\sin \theta =\dfrac{y}{r}=\dfrac{-15}{17} \\ \cos \theta =\dfrac{x}{r}=\dfrac{8}{17} \\ \tan \theta =\dfrac{y}{x}=\dfrac{-15}{8}$ and $\csc \theta =\dfrac{r}{y}=\dfrac{-17}{15} \\ \sec \theta =\dfrac{r}{x}=\dfrac{17}{8} \\ \cot \theta =\dfrac{x}{y}=\dfrac{-8}{15}$