## Precalculus (6th Edition) Blitzer

Published by Pearson

# Chapter 4 - Review Exercises - Page 644: 29

#### Answer

$1$

#### Work Step by Step

Since, $\sin^2 \theta +\cos^2 \theta=1$ Here, $\theta = \dfrac{\pi}{17}$ Thus, we have $\sin^2 (\dfrac{\pi}{17}) +\cos^2 (\dfrac{\pi}{17}) =1$

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