Answer
$\sin^2 (\dfrac{\pi}{7}) +\cos^2 (\dfrac{\pi}{7}) =1$
Work Step by Step
Since, $\sin^2 \theta +\cos^2 \theta=1$
Here, $\theta = \dfrac{\pi}{7}$
Thus, we have $\sin^2 (\dfrac{\pi}{7}) +\cos^2 (\dfrac{\pi}{7}) =1$
Precalculus (6th Edition) Blitzer
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13446-914-3
ISBN 13:
978-0-13446-914-0
Chapter 4 - Mid-Chapter Check Point - Page 577: 20
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
