## Precalculus (6th Edition) Blitzer

$\dfrac{\pi}{18} \text{ radians}$
Multiply $\dfrac{\pi \text{ radians}}{180^o}$ to the given angle measure to obtain: $=10 \cdot \dfrac{\pi \text{ radians}}{180^o} \\=\dfrac{\pi}{18} \text{ radians}$