Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 4 - Mid-Chapter Check Point: 3

Answer

$75^o$

Work Step by Step

Multiply $\dfrac{180^o}{\pi}$ to the given angle measure to obtain: $=\dfrac{5\pi}{12} \cdot \dfrac{180^o}{\pi} \\=\dfrac{900^o(\pi)}{12\pi} \\=75^o$
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