Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 3 - Test - Page 515: 9

Answer

$\ln \dfrac{7}{x^3}$

Work Step by Step

Recall the log rules: (a) $\log_b{p \cdot q} =\log p + \log q $ (b) $\log_b{\dfrac{p}{q}}=\log_b{p} - \log_b{q}$ (Quotient Rule). (c) $\log{a^n}=n \log x $ (d) $\log_a{a^x}=x $ Use the rule (b) with $ p=7$ and $ q=x^3$ to obtain $\ln 7- 3 \ln 7=\ln 7-\ln x^3 $ Simplify the second term by applying rule (c) to obtain: $ \ln 7-\ln x^3= \ln \dfrac{7}{x^3}$
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