## Precalculus (6th Edition) Blitzer

Published by Pearson

# Chapter 3 - Test - Page 515: 13

#### Answer

$277.2589$

#### Work Step by Step

Re-arrange as: $e^{0.005x}=4$ We need to take $\ln$ of each side of the equation. $\ln e^{0.005x} =\ln 4$ Simplify it by applying rule $\log{a^n}=n \log x$ to obtain: $0.005x= \ln 1.4$ This implies that $x = \dfrac{\ln 4}{0.005} \approx 277.2589$

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