Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 3 - Test - Page 515: 13

Answer

$277.2589$

Work Step by Step

Re-arrange as: $ e^{0.005x}=4$ We need to take $\ln $ of each side of the equation. $\ln e^{0.005x} =\ln 4$ Simplify it by applying rule $\log{a^n}=n \log x $ to obtain: $ 0.005x= \ln 1.4$ This implies that $ x = \dfrac{\ln 4}{0.005} \approx 277.2589$
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