Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 3 - Test - Page 515: 10



Work Step by Step

Use the log rule $\log_q p=\dfrac{\log p}{\log q}$ with $ p=71$ and $ q=15$ to obtain $\log_{15} 71=\dfrac{\log 71}{\log 15}$ Simplify: $\dfrac{\log 71}{\log 15} \approx 1.5741$
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