## Precalculus (6th Edition) Blitzer

$1.5741$
Use the log rule $\log_q p=\dfrac{\log p}{\log q}$ with $p=71$ and $q=15$ to obtain $\log_{15} 71=\dfrac{\log 71}{\log 15}$ Simplify: $\dfrac{\log 71}{\log 15} \approx 1.5741$