Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 3 - Test - Page 515: 11

Answer

$-10$

Work Step by Step

Replace $9$ by $3^2$ $3^{x-2} =[(3)^2]^{x+4}$ Use the distributive property $ a (b+c)=ab+ac $ $\implies 3^{x-2} =3^{2x+8}$ Simply to obtain: $ x-2 =2x+8 $ or, $ x=-10$
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