## Precalculus (6th Edition) Blitzer

Solution set = $\displaystyle \{\frac{\ln 659}{5}\}.$ $x\approx 1.30$
$3e^{5x}=1977\qquad$... divide with 3 $e^{5x}=659$ $\qquad$... apply ln( ) to both sides, (use: $\ln e^{M}=M$) $\ln e^{5x}=\ln 659$ $5x=\ln 659\qquad$... divide with $5$ $x=\displaystyle \frac{\ln 659}{5}\qquad$... round to 2 decimal places $x\approx 1.30$