Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 3 - Section 3.4 - Exponential and Logarithmic Equations - Exercise Set: 15

Answer

$x=5$

Work Step by Step

RECALL: (i) If $a^M=a^N$, then $M=N.$ (ii) $\sqrt[n]{a}=a^{\frac{1}{n}}.$ Use rule (ii) above to obtain $6^{\frac{x-3}{4}}=6^{\frac{1}{2}}.$ Use rule (i) above to obtain $\dfrac{x-3}{4}=\dfrac{1}{2}.$ Cross-multiply to obtain $\begin{array}{ccc} &2(x-3) &= &4(1) \\&2x-6 &= &4 \\&2x &= &4+6 \\&2x&= &10 \\&x &= &\dfrac{10}{2} \\&x &= &5 \\\end{array}.$
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