## Precalculus (6th Edition) Blitzer

$1+\log_7{x}$
RECALL: (i) $\log_b{MN}=\log_b{M} + \log_b{N}$ (Product Rule). (ii) $\log_b{b}=1.$ Use the product rule with $M=7$ and $N=x$ to obtain $\log_7{7} + \log_7{x}.$ Use rule (ii) above to obtain $1+\log_7{x}.$