Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 3 - Section 3.3 - Properties of Logarithms - Exercise Set: 16

Answer

$7 \cdot \log_b{x}$

Work Step by Step

RECALL: (1) $\log_b{\frac{M}{N}}=\log_b{M}-\log_b{N}$ (2) $\log_b{(b^x)}=x$ (3) $\log_b{(a^n)} = n \cdot \log_b{a}$ Use rule (3) above with $n=7$ to obtain $=7 \cdot \log_b{x}$
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