Answer
$2−\ln{5}$
Work Step by Step
RECALL:
(1) $\ln{\frac{M}{N}}=\ln{M}-\ln{N}$
(2) $\ln{(e^x)}=x$
Use rule (1) above with $M=e^2$ and $N=5$ to obtain
$=\ln{(e^2)}-\ln{5}$
Simplify the first term by using rule (2) above to obtain
$=2−\ln{5}$.
