Answer
$4−\ln{8}$
Work Step by Step
RECALL:
(1) $\ln{\frac{M}{N}}=\ln{M}-\ln{N}$
(2) $\ln{(e^x)}=x$
Use rule (1) above with $M=e^4$ and $N=8$ to obtain
$=\ln{(e^4)}-\ln{8}$
Simplify the first term by using rule (2) above to obtain
$=4−\ln{8}$