Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 3 - Section 3.1 - Exponential Functions - Exercise Set - Page 451: 97


See explanations.

Work Step by Step

Step 1. Replace $f(x)$ with $y$; we have $y=2^x$ Step 2. Switch $x$ and $y$; we have $x=2^y$ Step 3. Solving for $y$, we have $y=log_2(x)$, with $x\gt0$ Step 4. Replace $y$ with $f^{-1}(x)$, we get $f^{-1}(x)=log_2(x)$ with $x\gt0$ Step 5. We can see that a possible problem is that step 3 requires an advanced concept plus a restriction to the values of $x$.
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