## Precalculus (6th Edition) Blitzer

$x=1, -3\pm\sqrt {11}$
Step 1. List the possible rational zeros as $\frac{p}{q}=\pm1,\pm2$ Step 2. Use synthetic division to find a zero at $x=1$ as shown in the figure. Step 3. With the quotient $x^2+6x-2$, we can obtain the other two zeros as $x=\frac{-6\pm\sqrt {36+8}}{2}=-3\pm\sqrt {11}$ Step 4. We conclude that the zeros are $x=1, -3\pm\sqrt {11}$