## Precalculus (6th Edition) Blitzer

$a.\displaystyle \quad y=(\frac{1}{3})^{x}$ $b.\displaystyle \quad y=(\frac{1}{5})^{x}$ $c.\quad y=5^{x}$ $d.\quad y=3^{x}$
The always rising graphs (c and d) are graphs of the functions with bases greater than 1. The greater the base, the steeper the rise after crossing the y-axis. So, $(c)$ is $5^{x},\ \quad(d)$ is $3^{x}.$ $a$ is the reflection (about the y-axis) of $d$, so it is the graph of $3^{-x}=(\displaystyle \frac{1}{3})^{x}.$ $b$ is the reflection (about the y-axis) of $c$, so it is the graph of $5^{-x}=(\displaystyle \frac{1}{5})^{x}.$ $a.\displaystyle \quad y=(\frac{1}{3})^{x}$ $b.\displaystyle \quad y=(\frac{1}{5})^{x}$ $c.\quad y=5^{x}$ $d.\quad y=3^{x}$