## Precalculus (6th Edition) Blitzer

False. Replace "$f(a)+f(b)$" with "$f(a)\cdot f(b)$"
$f(a+b)=2^{a+b}=2^{a}\cdot 2^{b}=f(a)\cdot f(b)$ So, the statement is false. The simplest way to make it true is to replace "$f(a)+f(b)$" with "$f(a)\cdot f(b)$"