## Precalculus (6th Edition) Blitzer

$x=3, 1\pm\sqrt 2$; see graph.
Step 1. List possible rational zeros: $\frac{p}{q}=\pm1,\pm3$ Step 2. Test with synthetic division to find a zero at $x=3$, as shown in the figure. Step 3. The function becomes: $f(x)=-(x-3)(x^2-2x-1)$ Thus the zeros are $x=3, 1\pm\sqrt 2$ Step 4. Graph the function as shown in the figure.