## Precalculus (6th Edition) Blitzer

The standard form of the expression $\left( 6-2i \right)-\left( 7-i \right)$ is $-1-i$.
Consider the expression, $\left( 6-2i \right)-\left( 7-i \right)$ Remove the parentheses. $\left( 6-2i \right)-\left( 7-i \right)=6-2i-7+i$ Combine the real part and the imaginary part. \begin{align} & \left( 6-2i \right)-\left( 7-i \right)=\left( 6-7 \right)+\left( 1-2 \right)i \\ & =-1-i \end{align} Therefore, the standard form of the expression $\left( 6-2i \right)-\left( 7-i \right)$ is $-1-i$.