Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 2 - Mid-Chapter Check Point - Page 381: 16

Answer

The zeros of $f\left( x \right)=-{{\left( x+1 \right)}^{6}}$ are $-1,-1,-1,-1,-1,-1$.

Work Step by Step

Let’s first equate $f\left( x \right)$ to $0$. So, $-{{\left( x+1 \right)}^{6}}=0$ It can also be written as: $-\left( x+1 \right)\left( x+1 \right)\left( x+1 \right)\left( x+1 \right)\left( x+1 \right)\left( x+1 \right)=0$ So, the zero of the provided function is $x=-1$ with the multiplicity of $6$. The graph touches the x- axis and turns around at $-1$ since it has multiplicity 6. Also, since the function is an even-degree polynomial and the leading coefficient is $-1$, the graph will fall downwards.
Small 1569549579
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.