Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 11 - Section 11.1 - Finding Limits Using Tables and Graphs - Exercise Set - Page 1142: 102


$\frac{1}{\sqrt {4+x}+2}$

Work Step by Step

Multiplying the conjugate of the numerator, we have $\frac{\sqrt {4+x}-2}{x}=\frac{\sqrt {4+x}-2}{x}\times\frac{\sqrt {4+x}+2}{\sqrt {4+x}+2}=\frac{4+x-4}{x(\sqrt {4+x}+2)}=\frac{1}{\sqrt {4+x}+2}$
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