Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 11 - Section 11.1 - Finding Limits Using Tables and Graphs - Exercise Set - Page 1142: 101



Work Step by Step

Factoring the numerator, we have $\frac{x^2-x-6}{x-3}=\frac{(x+2)(x-3)}{x-3}=x+2$ (provided $x\ne 3$)
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