## Precalculus (6th Edition) Blitzer

a. See graph. b. $\lim_{x\to2^-}f(x)=9$, $\lim_{x\to2^+}f(x)=7$; $\lim_{x\to2}f(x)$ does not exist.
a. We can graph both functions on the same plot as shown in the figure. b. Based on the graph, we have $\lim_{x\to2^-}f(x)=9$ $\lim_{x\to2^+}f(x)=7$ Since $\lim_{x\to2^-}f(x)\ne \lim_{x\to2^+}f(x)$ We conclude that $\lim_{x\to2}f(x)$ does not exist.