Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 11 - Section 11.2 - Finding Limits Using Properties of Limits - Concept and Vocabulary Check - Page 1152: 1

Answer

The correct fill for the blank provided in the expression “$\underset{x\to a}{\mathop{\lim }}\,\text{ }c=$______” is $\underset{x\to a}{\mathop{\lim }}\,\text{ }c=c $.

Work Step by Step

The limits involving a constant function give the same constant as the result. That is: For the constant function $ f\left( x \right)=c $, $\begin{align} & \underset{x\to a}{\mathop{\lim }}\,f\left( x \right)=\underset{x\to a}{\mathop{\lim }}\,\text{ }c \\ & =c \end{align}$ Where $ a $ is any number. The limit of any constant is that constant regardless of what number $ x $ approaches. Therefore, the correct fill for the blank provided in the expression “$\underset{x\to a}{\mathop{\lim }}\,\text{ }c=$______” is $\underset{x\to a}{\mathop{\lim }}\,\text{ }c=c $.
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