## Precalculus (6th Edition) Blitzer

The correct fill for the blank provided in the expression “$\underset{x\to a}{\mathop{\lim }}\,\text{ }c=$______” is $\underset{x\to a}{\mathop{\lim }}\,\text{ }c=c$.
The limits involving a constant function give the same constant as the result. That is: For the constant function $f\left( x \right)=c$, \begin{align} & \underset{x\to a}{\mathop{\lim }}\,f\left( x \right)=\underset{x\to a}{\mathop{\lim }}\,\text{ }c \\ & =c \end{align} Where $a$ is any number. The limit of any constant is that constant regardless of what number $x$ approaches. Therefore, the correct fill for the blank provided in the expression “$\underset{x\to a}{\mathop{\lim }}\,\text{ }c=$______” is $\underset{x\to a}{\mathop{\lim }}\,\text{ }c=c$.