Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 11 - Review Exercises - Page 1179: 53


$-9$ and $ y=-9x-5$

Work Step by Step

Now, $ m_{\tan}=\lim_\limits{ h\to 0} \dfrac{f(-1+h)-f(-1)}{h}$ or, $=\lim_\limits{ h\to 0} \dfrac{(h-1)^2-7(h-1)-4-(-1)^2+7(-1) +4}{h}$ or, $=\lim_\limits{ h\to 0} \dfrac{h^2-9h}{h}$ or, $=-9$ The equation of a line is: $ y=mx+c $ Now, $ y-4=-9(x+1) \implies y=-9x-5$
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