Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 11 - Review Exercises - Page 1179: 41



Work Step by Step

Recall that if $ f $ is a polynomial function, then we have $\lim_\limits{x\to a}f(x)=f(a)$. $ f(x)=3x^2-2x+1$ Set $ a=4$ $ f(4)=3(4)^2-2(4)+1=41$ So, $ f(4)$ is defined. Now, $\lim_\limits{x\to 4} f(x)=3\lim_\limits{x\to 4} x^2-2 \lim_\limits{x\to 4} x+1=3(4)^2-2(4)+1=41$ So, $ f(x)$ exists. Therefore, the function is continuous at $ x=4$
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