Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 11 - Review Exercises - Page 1179: 42


Discontinuous at $ x=-3$

Work Step by Step

Recall that if $ f $ is a polynomial function, then we have $\lim_\limits{x\to a}f(x)=f(a)$. $ f(x)=\dfrac{x^2-9}{x+3}$ Set $ x=-3$ $ f(-3)=\dfrac{(-3)^2-9}{-3+3}=0$ So, $ f(-3)$ is not defined. Therefore, the function is discontinuous at $ x=-3$
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