Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 11 - Review Exercises - Page 1179: 52


$9$ and $ y=9x-2$

Work Step by Step

Now, $ m_{\tan}=\lim_\limits{ h\to 0} \dfrac{f(1+h)-f(1)}{h}$ or, $=\lim_\limits{ h\to 0} \dfrac{2(1+h)^2+(5+h)-2(1)^2-(5)(1)}{h}$ or, $=\lim_\limits{ h\to 0} \dfrac{2h^2+9h}{h}$ or, $=9$ The equation of a line is: $ y=mx+c $ Now, $ y-7=9(x-1) \implies y=9x-2$
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