Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 10 - Section 10.3 - Geoetric Sequences and Series - Exercise Set - Page 1074: 68

Answer

$\$38288$

Work Step by Step

The general formula to find the nth term of a Geometric sequence is given as: $ a_{n}=a_1r^{n-1}$ Here, we have $ a_1= 30,000$ and the common ratio, $ r=1.05$ Now, $ a_{6}=30,000 \times (1.05)^{6-1}=30,000 \times (1.05)^{5}=38288$
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