Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 10 - Section 10.3 - Geoetric Sequences and Series - Exercise Set - Page 1074: 30


$ S_{14}=\dfrac{5461}{24}=227.54$

Work Step by Step

The general formula to find the nth partial sum of a Geometric sequence is given as: $ S_{n}=\dfrac{a(1-r^n)}{(1-r)}$ $ r=\dfrac{a_2}{a_1}=\dfrac{1/12}{-1/24}=-2$ and $ n=14$ Now, $ S_{14}=\dfrac{\dfrac{-1}{24} \times (1-(-2)^{14})}{(1-(-2))}=\dfrac{-1}{24} \times (-5461)$ Our answer is: $ S_{14}=\dfrac{5461}{24}=227.54$
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