Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 10 - Section 10.3 - Geoetric Sequences and Series - Exercise Set - Page 1074: 57



Work Step by Step

We are given that the sequence $ a_n $ is an arithmetic sequence and the sequence $ b_n $ is a geometric sequence. Here, we have $ r=-2$ and $ d=-15$ The general formula to find the nth term of a Geometric sequence is given as: $ a_{n}=a_1r^{n-1}$ Thus, $ a_{10}=a_1r^{10-1} =(-5)(-2)^9 =2560$ The general formula to find the nth term of an arithmetic sequence is given as: $ a_{n}=a_1+(n-1) d $ and $ b_{10}=10+(10-1) (-15) =10-135=-125$ Now, $ a_{10}+b_{10}=2560-125=2435$
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