Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 10 - Section 10.3 - Geoetric Sequences and Series - Exercise Set - Page 1074: 36



Work Step by Step

The general formula to find the nth partial sum of a Geometric sequence is given as: $ S_{n}=\dfrac{a(1-r^n)}{(1-r)}$ $ a_1=(\dfrac{1}{3})^{1+1}=\dfrac{1}{9}$ for $ i=1$ Now, $ S_{6}=\dfrac{(\dfrac{1}{9}) \times [1-(\dfrac{1}{3})^{6}]}{[1-(\dfrac{1}{3})]}=\dfrac{1}{9} \times (\dfrac{364}{243})$ Our answer is: $ S_{6}=\dfrac{364}{2187}$
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