Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 10 - Section 10.2 - Arithmetic Sequences - Exercise Set - Page 1061: 91



Work Step by Step

The sum of an arithmetic sequence is given by: $S_n=\dfrac{n}{2}[a_1+a_n]$ and the nth term for an arithmetic sequence is given by $a_n=a_1+(n-1) d$ We are given that $11,33, 99, 297,......$ This gives: $a_n=a_1 \cdot 3^{n-1} $ Here, $a_7=11 \cdot 3^{7-1} =11 \cdot 3^{6}$ Hence, $a_7=8019$
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