Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 10 - Section 10.2 - Arithmetic Sequences - Exercise Set - Page 1061: 87

Answer

The solution of the giving expression is $ x=9$.

Work Step by Step

It is given that ${{\log }_{2}}\left( \frac{x+9}{x} \right)=1$ $\begin{align} & \log \left( \frac{x+9}{x} \right)=\log \,2 \\ & \frac{x+9}{x}=2 \\ & x+9=2x \\ & x=9 \end{align}$ Therefore, the solution of the giving expression is $ x=9$.
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