Answer
Company B pays the greater amount.
Work Step by Step
Company A:
$\begin{align}
& {{a}_{n}}=19,000+\left( n-1 \right)2600 \\
& {{a}_{n}}=19,000+9\left( 2600 \right) \\
& {{a}_{n}}=\$42,400\\\end{align}$
So, $\begin{align}
& {{S}_{n}}=\frac{n}{2}\left( {{a}_{1}}+{{a}_{n}} \right) \\
& {{S}_{n}}=\frac{10}{2}\left( 19000+42400 \right) \\
& {{S}_{n}}=\$307,000\\\end{align}$
Company B:
$\begin{align}
& {{a}_{n}}=27,000+\left( n-1 \right)1200 \\
& {{a}_{10}}=27,000+9\left( 1200 \right) \\
& {{a}_{10}}=\$37,800\\\end{align}$
So, $\begin{align}
& {{S}_{n}}=\frac{n}{2}\left( {{a}_{1}}+{{a}_{n}} \right) \\
& {{S}_{n}}=\frac{10}{2}\left( 27,000+37,800 \right) \\
& {{S}_{n}}=\$324,000\\\end{align}$
