## Precalculus (6th Edition) Blitzer

$300,350,400,450,500,550$
Formula to calculate the nth term of an arithmetic sequence is: $a_n=a_1+d(n-1)$ Here, $a_1:$ First term and $d=$ common difference $a_1=300+50(1-1)=300$; $a_2=300+50(2-1)=350$;$a_3=300+50(3-1)=400$;$a_4=300+50(4-1)=450$; $a_5=300+50(5-1)=500$;$a_6=300+50(6-1)=550$ Hence, the first six terms are: $300,350,400,450,500,550$