Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 10 - Section 10.2 - Arithmetic Sequences - Exercise Set - Page 1059: 9

Answer

$-9,-3,3,9,15,21$

Work Step by Step

Formula to calculate the nth term of an arithmetic sequence is: $a_n=a_1+d(n-1)$ Here, $a_1: $ First term and $d=$ common difference Since, we have $a_1=-9$ Use a recursion formula to find the remaining five terms. Then $a_2=a_1+6=-9+6=-3;\\a_3=a_2+6=-3+6=3;\\a_4=a_3+6=3+6=9;\\a_5=a_4+6=9+6=15;\\a_6=a_5+6=15+6=21$ Hence, the first six terms are: $-9,-3,3,9,15,21$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.