Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 10 - Section 10.2 - Arithmetic Sequences - Exercise Set - Page 1059: 5



Work Step by Step

Formula to calculate the nth term of an arithmetic sequence is: $a_n=a_1+d(n-1)$ Here, $a_1: $ First term and $d=$ common difference $a_1=300+(-90)(1-1)=300; \\a_2=300+(-90)(2-1)=210;\\a_3=300+(-90)(3-1)=120;\\a_4=300+(-90)(4-1)=30; \\a_5=300+(-90)(5-1)=-60;\\a_6=300+(-90)(6-1)=-150$ Hence, the first six terms are: $300,210,120,30,-60,-150$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.