Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 10 - Section 10.2 - Arithmetic Sequences - Exercise Set - Page 1059: 6

Answer

$200,140,80,20,-40,-100$

Work Step by Step

Formula to calculate the nth term of an arithmetic sequence is: $a_n=a_1+d(n-1)$ Here, $a_1: $ First term and $d=$ common difference $a_1=200+(-60)(1-1)=200; \\a_2=200+(-60)(2-1)=140;\\a_3=200+(-60)(3-1)=80;\\a_4=200+(-60)(4-1)=20; \\a_5=200+(-60)(5-1)=-40;\\a_6=200+(-60)(6-1)=-100$ Hence, the first six terms are: $200,140,80,20,-40,-100$
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