## Precalculus (6th Edition) Blitzer

Published by Pearson

# Chapter 10 - Section 10.1 - Sequences and Summation Notation - Exercise Set - Page 1051: 99

False

#### Work Step by Step

Need to check the formula. $\sum_{ i=1}^ 2(-1) ^i 2^i=0$ Then, $\sum_{ i=1}^ 2(-1) ^i 2^i=(-1)^1 \cdot 2^1+(-1)^2 \cdot 2^2=2$ But $2 \neq 0$ This implies that $\sum_{ i=1}^ 2(-1) ^i 2^i \neq 0$ Hence, the statement is false.

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