#### Answer

amplitude $\frac{1}{2}$, period $\frac{2\pi}{3}$, phase $-\frac{\pi}{6}$, see graph

#### Work Step by Step

Step 1. Given
$y=\frac{1}{2}cos(3x+\frac{\pi}{2})=\frac{1}{2}cos3(x+\frac{\pi}{6})$
we can identify its amplitude as $|A|=\frac{1}{2}$, period as $p=\frac{2\pi}{3}$, and phase shift as $\phi=-\frac{\pi}{6}$.
Step To graph the function, start from $y=\frac{1}{2}sin(x)$, shift $\frac{\pi}{6}$ to the left, then shrink horizontally by a factor of $3$ as shown in the figure.