## Precalculus (6th Edition) Blitzer

$9, 32, 16, 8, 4$
Here, $a_1=9$ ; odd term Thus, $a_2=3 \times 9 +5=32$ and $a_2=32$ ; Even term Thus, $a_3=\dfrac{32}{2}=16$ In the similar way, we have $a_4=\dfrac{16}{2}=8$ and $a_5=\dfrac{8}{2}=4$ Hence, the first five terms of the sequence are $9, 32, 16, 8, 4$